蕲春天气预报:x÷(1/x-1/y)=?
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x÷(1/x-1/y)
=x÷[(y-x)/xy]
=x*[xy/(y-x)]
=x^2*y/(y-x)
x÷(1/x-1/y)=x*x-x*y
x÷(1/x-1/y) 先把括号里通分
=x÷((y-x)/xy)
=x*x-x*y
x*x*y/(y-x)
x/(1/x-1/y)=x/[(y-x)/xy]=x^2y/(y-x)=x^2-xy
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已知X+Y=-4,求1/2(X+Y)+4(X-Y)-3(X-Y)-3/2(X+Y)-X+Y
x÷(1/x-1/y)=?
2/(x-y)+x/y-1/x
已知数x、y、z满足x/y+z + y/z+x +z/x+y=1,求
x, y>0。求证x/y+y/x+xy>x+y+1
x^2+y^2+1/2=x+y,则x= ,y= .
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已知x,y都大于等于零,求证1/2(x+y)^2+1/4(x+y)>=x√y+y√x
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