take one组合:2/（x-y)+x/y-1/x

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（分式计算，要有过程）谢啦！！！

原式=2/(x-y)=1/(y-1)
=2(y-1)/(x-y)(y-1)+(x-y)/(x-y)(y-1)
=(2y-2+x-y)/(x-y)(y-1)
=y+x-2/xy-x-y的平方+y

原式=2xy/xy(x-y)+x方(x-y)/xy(x-y)-(x-y)y/xy(x-y)
=(2xy+x^3-x^2y-xy+y^2)/xy(x-y)
=(x^3+xy+y^2-x^2y)/xy(x-y)

2X的平方减Y对不对啊

1/4(x+y)+1/2(x+y)*(x+y)>=x*根号y+y*根号x 2/（x-y)+x/y-1/x 已知,X-Y/X=X/(X-2Y)(Y不等于0)求X/Y的值 已知X+Y=-4，求1/2（X+Y)+4(X-Y)-3(X-Y)-3/2(X+Y)-X+Y 若 x/3y = y/2x-5y =6x-15y/x 求1/4(x+y)+1/2(x+y)*(x+y)的最值 x^2+y^2+1/2=x+y,则x= ,y= . 列举法表示(x,y)/x+y=2,x-2y=4 列举法表示 (x,y)/x+y=2 x-2y=4 (x+2y)(x+y)=4XX-5xy-6yy 求x/y