银行只能应届生考吗:·高一数学·

来源:百度文库 编辑:神马品牌网 时间:2024/05/05 22:08:55
函数y=(cos^6)x+(sin^6)x的最小正周期是()
怎么做的??

=((Cos^2)x)^3+((Sin^2)x)^3
=[(Sin^2)x+(Cos^2)x][(Sin^4)x-(Sin^2)x*(Cos^2)x+(Cos^4)x]
=[(Cos^4)x+2(Sin^2)x*(Cos^2)x+(Sin^4)x-3(Sin^2)x*(Cos^2)x]
=1-3(Sin^2)x*(Cos^2)x
=5/8+3/8*(Cos4x)
故最小正周期:2Pi/4=Pi/2

y=(cos^6)x+(sin^6)x=<(cos^2)x+(sin^2)x><(cos^4)x+(sin^4)x-(cos^2)x(sin^2)x>=<(cos^2)x+(sin^2)x>^2-3(cos^2)x(sin^2)x=1-3(cos^2)x(sin^2)x=1-3/4(sin^2)2x=(5+3cos4X)/8
最小正周期是90度(请化成弧度制)

gbjn