老九门贝勒爷姓什么:12345*54321=?我要简便方法

用计算机算不？？？？~~~~~哈哈
我想是这样但不知道对不对啊！！！！！
(10000+2000+300+40+5)X54321
解:原式=543210000+108642000+16296300+2172840+271605
=670592745

赫赫,想不出来,如果一楼的回答对的话,这个式子应该也对
12345×（50000+4000+300+20+1）
其实这是把横式化成等式来计算的，更麻烦。

好像没什么好算的吧

For example - // For example -
// reverse() on "12345" returns "54321" // reverse() on "12345" returns "54321"
String tmpstr(val); String tmpstr(sval);
char aa; tmpstr._reverse();
unsigned long tot_len = length(); return tmpstr;
unsigned long midpoint = tot_len / 2; }
for (unsigned long tmpjj = 0; tmpjj < midpoint; tmpjj++)
// Imitate Java's valueOf string function...
String String::valueOf(char chars[], int startIndex, int numChars)
{ {
aa = tmpstr.val[tmpjj]; // temporary storage var verifyIndex(startIndex);
tmpstr.val[tmpjj] = tmpstr.val[tot_len - tmpjj - 1]; // swap the values int ii = strlen(chars);
tmpstr.val[tot_len - tmpjj - 1] = aa; // swap the values if (startIndex > ii)
{
cerr << "\nvalueOf() - startIndex greater than string length of"
<< "string passed" << endl;
exit(0);
}
if ( (numChars+startIndex) > ii)
{
cerr << "\nvalueOf() - numChars exceeds the string length of"
<< "string passed" << endl;
exit(0);