burberry手表怎么样:已知数列{log2(an-1)}(n属于N*)为等差数列,且a1=3,a3=9,求数列{an}的通项公式.

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已知数列{log2(an-1)}(n属于N*)为等差数列,且a1=3,a3=9,求数列{an}的通项公式.
请详细说一下过程~谢谢!

log2(a1-1)=log2(2)=1
log2(a3-1)-log2(a1-1)=2d
d=[log2(8)-log2(2)]/2=1
log2(an-1)=1+(n-1)*1=n
2^n=an-1
an=2^n+1

d=log2(an-1)-log2(a(n-1)-1)
=log2((an-1)/(a(n-1)-1))
则p=(an-1)/(a(n-1)-1)为定值
n=2 p=(a2-1)/2
n=3 p=8/(a2-1)
a2=5(an大于1)
p=2,d=1
2=(an-1)/(a(n-1)-1)
an=2a(n-1)-1
an=2^n+1

d=log2(an-1)-log2(a(n-1)-1)
=log2((an-1)/(a(n-1)-1))
则p=(an-1)/(a(n-1)-1)为定值
n=2 p=(a2-1)/2
n=3 p=8/(a2-1)
a2=5(an大于1)
p=2,d=1
2=(an-1)/(a(n-1)-1)
an=2a(n-1)-1
an=2^n+1

设bn=n
㏒2﹙an-1﹚=n
an-1=2^n
an=2^n+1