神马品牌网第六代导演作品:请大家帮忙解一道数学题
来源：百度文库 编辑：神马品牌网 时间：2024/05/01 22:27:29
(x-y)(x-y)+(x+y)(y-x)+0.25(x+y)(x+y)
要求分解因式
要求分解因式
原式=(x-y)^2-2*0.5*(x+y)*(x-y)+(0.5)^2*(x+y)
=(x-y-0.5x-0.5y)^2
=(0.5x-0.5y)^2
=0.25(x-y)^2
[(x-y)-1/2(x+y)]^2
a^2=a*a
(x-y)(x-y)+(x+y)(y-x)+0.25(x+y)(x+y)
解：原式=2.25（x*x)-1.5xy+0.25(y*y)
原式=(x-y)^2-2*0.5*(x+y)*(x-y)+(0.5)^2*(x+y)
=(x-y-0.5x-0.5y)^2
=(0.5x-0.5y)^2
=0.25(x-y)^2
(x-y)(x-y)+(x+y)(y-x)+0.25(x+y)(x+y)
原式=0.25[4(x-y)^2-4(x-y)(x+y)+(x+y)^2]
=0.25[2(x-y)-(x+y)]^2
=0.25(x-3y)^2