y^4+2x^4+1-4x^2y=02(x^4-2x^2y+y^2)+y^4-2y^2+1=02(x^2-y)^2+(y^2-1)^2=0即y^2-1=0 x^2-y=0得(x,y)为(1,1),(-1,1)
(1,1)