上海印刷机械行业协会:一辆客车长190,一辆货车290,两车长比为5:3,两车同向行驶交叉为1分钟,相向行驶交叉多少分钟?

来源:百度文库 编辑:神马品牌网 时间:2024/05/01 09:15:33

设货车车长为3X,客车的车长为5X,
得出方程
(290-190)*1=5X+3X
得出X=25/2

相向行驶交叉
(25/2*(3+5))/(190+290)
=100/480

分钟

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