小米路由器磁盘映射:初二分式方程:[2+1/(x-1)-1/(1-x)]/[x-x/(1-x*x)]求详细解

[2+1/(x-1)-1/(1-x)]/[x-x/(1-x*x)]
=[2+1/(x-1)+1/(x-1)]/{x[1+/(x*x-1)]}
=2[1+1/(x-1)]/{x[1+1/(x*x-1)]}
=2(x-1+1)/(x-1)/{x[(x*x-1+1)/(x*x-1)]}
=2x/(x-1)/{x[(x*x/(x*x-1)]}
=2/(x-1)/x*x*(x*x-1)
=2(x+1)/x*x
可以吗?

原式=[2+1/(x-1)+1/(x-1)]/{x[1-1/(1-x^2)]}
=2[1+1/(x-1)]/{x[1+1/(x^2-1)]}
=2(x-1+1)/(x-1)/{x[(x^2-1+1)/(x^2-1)]}
=2x/(x-1)/{x[(x^2/(x^2-1)]}
=2/(x-1)/x^2*(x^2-1)
=2(x+1)/x^2

[2+1/(x-1)-1/(1-x)]/[x-x/(1-x*x)]
=[2+1/(x-1)+1/(x-1)]/[x+x/(x*x-1)]
=[2+2/(x-1)]/[x+x/(x*x-1)]
=[2（x-1）+2/(x-1)]/[x^3/(x^2-1)] 说明：x^3表示x的3次方 ，x^2表示x的2次方
=[2（x-1）+2/(x-1)]*[(x^2-1)/x^3]
=[2（x-1）+2](x+1)/x^3
=2x(x+1)/x^3
=2(x+1)/x^2

[2+1/(x-1)-1/(1-x)]/[x-x/(1-x*x)]
其中2+1/(x-1)-1/(1-x)=2+1/(x+1)-[-1/(x-1)]=2+1/(x+1)+1/(x-1)=2+2/(x+1)=(2x+2)/(x+1)+2/(x+1)=(2x+4)/(x+1)
[x-x/(1-x*x)]=x[1-1/(1-x*x)]=x[(1-x*x)/(1-x*x)-1/(1-x*x)]=x[(1-x*x-1)/(1-x*x)]=-x(x*x/1-x*x)=x*x*x/(1-x)(1+x)
原式=(2x+4)/(x+1)除以x*x*x/(1-x)(1+x)即
=(2x+4)/(x+1)*(1-x)(1+x)/x*x*x=(2x+4)*(1-x)/x*x*x
问题有些看不清