罗马利奥瓷砖怎么样:问你们一条稍微难点的问题
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Let y=f(x)=3^(1/2) *SinX+cosX for 0<=x<=2PI
Find the maximum point and minimun point of the graph of y=f(x)
Find the maximum point and minimun point of the graph of y=f(x)
这么简单。。
f(x)=3^(1/2) *SinX+cosX=2[3^(1/2)/2sinx+1/2cosx]=2cos(x-30)
0<=x<=2PI
-30<=x-30<=2PI -30
f(x)maximum=2
f(x)=minimun =-2