北京凝华雕铣机怎么样:char a[]="It is me"是不是说a中只能存放8个字符啊?

来源：百度文库编辑：神马品牌网时间：2024/04/27 15:32:12

我的理解
char a[]="It is me";
等价于
char a[9]="It is me";
其中a[8]='\0';
数组中只能存放8个ASCII码字符
而a只是一个指针，指向a[0]

经验证,楼上的cout<<sizeof a;为9~~^Q^

#include <iostream>

using namespace std;

void main()
{
char a[]="it is me";//这里其实定义了a[9],因为字符串最后会有一个'\0'结尾~
cout<<sizeof a;//=9
}

char a[]="It is me"
这样就隐式的定义了a[8],
a只有8个字符,不信可以用 cout<<sizeof a看看就明白了.

char a[]="it is me";//这里其实定义了a[9],因为字符串最后会有一个'\0'结尾,但也不表示只能存放8个字符,size是随你自己定义大小的,比如int size=19;看你需要多大

不是

只是 a 初始化时有 8 个字符

不是的
看你初始化时有几个字符了
还要加上个'/0'空字符

char a[]="It is me"是不是说a中只能存放8个字符啊? char a[10]="";是什么意思？ c++ 求助，char>="a"错误？英语题 Where is "A"? 1It's 2It is'nt it is a truth is it a story? Why is it called a "building" when it's already built? main() {char *s1 = "abcdeg"; char *s2="a"; s1++; s2++; printf ("%d\n",strcmp(s1,s2));} It is your turn=( ) a:It is your line b:It is your row c:You are next d:It is your chance it is not a translation