中组部常务副部长 省长:各位,能帮我解答一下这个问题吗? 因式分解:x(x+1)(x-1)+xy(x-y)-y(y-1)(y+1)=?

x(x+1)(x-1)+xy(x-y)-y(y-1)(y+1)
x(xx-1)+xy(x-y)-y(yy-1)
xxx-x+xxy-xyy-yyy+y
xxx-yyy+(xy+1)(x-y)
(x-y)(xx+xy+yy)+(xy+1)(x-y)
(x-y)(xx+xy+yy+xy+1)
本人不会打平方,不知能否看懂,悬赏我不要了,娱乐而已
不过我希望楼主表扬一下我,老师表扬我我都特别开心,我初一,就爱表扬

X3—X+X2Y—XY2—Y3+Y
X3—Y3—X+X2Y—XY2+Y
（X—Y）(X2+Y2+XY)+（XY+1）（X—Y）
（X—Y）（X2+Y2+2XY+1`）

x(x+1)(x-1)+xy(x-y)-y(y-1)(y+1)
=x(x^2-1)+xy(x-y)-y(y^2-1)
=x^3-x+xy(x-y)-y^3+y
=x^3-y^3-(x-y)+xy(x-y)
=(x-y)(x^2+xy+y^2)-(x-y)+xy(x-y)
=(x-y)(x^2+xy+y^2-1+xy)
=(x-y)(x^2+2xy+y^2-1)
=(x-y)((x-y)^2-1)
=(x-y)(x-y+1)(x-y-1)
注：x^2 x的平方 x^3 x的立方

x(x+1)(x-1)+xy(x-y)-y(y-1)(y+1)=?

x(x^2-1)+xy(x-y)-y(y^2-1)
......
做到这步看见上面有解答了.....

原式=x(x²-1)+xy(x-y)-y(y²-1)
=x³-x-y³+y+xy(x-y)
=x³-y³-(x-y)+xy(x-y)
=(x-y)(x²+xy+y²)+(x-y)(xy-1)
=(x-y)(x²+2xy+y²-1)
=(x-y)[(x+y)²-1]
=(x-y)(x+y-1)(x+y+1)
就这样

猜出x=y是一个解，再用除法。
(x - y)(-1+ x^2 + xy + x y + y ^2)