不义联盟人间之神手柄:s=5 for i 2.6 to 4.9 step 0.6 s=s+1 next i 是怎样解的啊
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s=5
for i 2.6 to 4.9 step 0.6
s=s+1
next i
求高手帮忙啊!
for i 2.6 to 4.9 step 0.6
s=s+1
next i
求高手帮忙啊!
s=5
从i=2.6开始,每次i加0.6(直到i>4.9),s加1
如果i>4.9
则停止.
这个结果是9么 亲 我这书上答案是8啊 我算的也是9
i 由 2.6 到 4.9, 每次回圈 i + 0.6 翅 到4.9 或最接近 4.9(少於4.9)便完结回圈
而s开始值是5, 每次回圈 s 加 1, 直到回圈结束
S=9
当验证程序的时候最好的方法是用print 语句,在你的这段程序后面加上print s,print i就可以看到你运行的结果了,s=9,i=5.0这样你就了解你所运算程序了。
s=5 for i 2.6 to 4.9 step 0.6 s=s+1 next i 是怎样解的啊
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