模卡制作app哪个好用:初二数学~~求助

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4x⒉ -4xy -3y⒉ -4x +10y -3 分解因式,求步骤

4x⒉ -4xy -3y⒉ -4x +10y -3
(如果“⒉”是平方的话,如下)
=(2x)^2 - 2 * 2x * y + y^2 - 4y^2 - 4x + 10y - 3
=(2x-y)^2 - (4y^2 - 4y + 1 + 4x + 2 - 6y)
=(2x-y)^2 - [(2y^2) - 2 * 2y * 1 + 1] - 4x - 2 + 6y
=(2x-y)^2 - (2y - 1)^2 - 2(2x + 1 - 3y)
=(2x - y + 2y - 1)(2x - y - 2y + 1)-2(2x + 1 - 3y)
=(2x + y - 1)(2x - 3y + 1)-2(2x - 3y + 1)
=(2x - 3y + 1)(2x + y - 1 - 2)
=(2x - 3y + 1)(2x + y - 3)

4x2-4xy-3y2 -4x +10y –3
=4x2-4xy+y2-4y2-4x+10y-3
=(2x-y)2-(4y2-4y+1)-4x-2+6y
=(2x-y)2-(2y-1)2-(4x-6y+2)
=(2x-y+2y-1)(2x-y-2y+1)- (4x-6y+2)
=(2x+y-1)(2x-3y+1)-2(2x-3y+1)
=(2x-3y+1)(2x+y-3)

4x2-4xy-3y2 -4x +10y –3
原式=4x2-4xy+y2-4y2-4x+10y-3
=(2x-y)2-(4y2-4y+1)-4x-2+6y
=(2x-y)2-(2y-1)2-(4x-6y+2)
=(2x-y+2y-1)(2x-y-2y+1)- (4x-6y+2)
=(2x+y-1)(2x-3y+1)-2(2x-3y+1)
=(2x-3y+1)(2x+y-3)

我是数学课代表~:
4x2-4xy-3y2-4x+10y3
=4x2-4xy+y2-4y2-4x+10y-3
=(2x-y)2-(4y2-4y+1)-4x-2+6y
=(2x-y)2-(2y-1)2-(4x-6y+2)
=(2x-y+2y-1)(2x-y-2y+1)- (4x-6y+2)
=(2x+y-1)(2x-3y+1)-2(2x-3y+1)
=(2x-3y+1)(2x+y-3)

4x2-4xy-3y2 -4x +10y –3
=4x2-4xy+y2-4y2-4x+10y-3
=(2x-y)2-(4y2-4y+1)-4x-2+6y
=(2x-y)2-(2y-1)2-(4x-6y+2)
=(2x-y+2y-1)(2x-y-2y+1)- (4x-6y+2)
=(2x+y-1)(2x-3y+1)-2(2x-3y+1)
=(2x-3y+1)(2x+y-3)