成立的近义词是什么:帮忙翻译

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3.5. Mechanisms for methanol steam reforming
Pour et al. [39] suggested that methanol conversion in the presence of water follows two steps. The first is methanol decomposition: CH3OH → CO + 2H2 (9) The second is the water gas shift reaction: CO + H2O → CO2 + H2 (8)

More recently, Takezawa and Iwasa [40], on the basis of finding formaldehyde and formic acid intermediates, has proposed a new pathway for methanol steam reforming over copper-based catalysts:

CH3OH → HCHO + H2 (10)
HCHO + H2O → HCOOH + H2 (11)
HCOOH → CO2 + H2 (12)
2HCHO → CH3OCHO (13)
CH3OCHO → CH3OH + CO (14)
CO + H2O → CO2 + H2 (8)

It is clear from Fig. 5 that the presence of Co enhanced the activity for the MSR. Furthermore, it can be
seen from Fig. 6 that although the selectivity for CO formation was greater than that over pure skeletal copper, the selectivity for CO2 formation was in excess of 80% even when the Co concentration was more than 1 wt.%. From Fig. 4 it can be seen that skeletal copper containing this level of Co had negligible activity for the water gasshift reaction. Therefore, we can conclude that the mechanism proposed by Pour et al. [39] is not correct for the copper-catalyzed MSR reaction and that the mechanism proposed by Takezawa and Iwasa [40] is more plausible. Furthermore, it appears that the mechanism represented by Eqs. (10)–(12) predominates for copper-based catalysts and that the mechanism represented by Eqs. (10)-(8) is less dominant.

The presence of Cr2O3 and ZnO favored the WGS reaction (Eq. (8)) and accounted for the reduced selectivity for CO formation, whereas the presence of Co made the Cu surface inactive for the WGS reaction, thereby accounting for the observed increase in CO selectivity. The results of this study are consistent with Takezawa and Iwasa’s [40] explanation of the mechanism for the MSR reaction and the findings of Jiang et al. [41] using a Cu-ZnO/Al2O3 catalyst.

3.5. 甲醇蒸汽重整机理
Pour 等[39] 指出甲醇在水存在的条件下的转化遵从两个步骤。第一步是甲醇分解:CH3OH → CO + 2H2 (9);第二步是水气转化反应:CO + H2O → CO2 + H2 (8)
最近Takezawa和Iwasa [40] 采用甲醛和甲酸作为反应中间体,has proposed a new pathway for 提出了一条铜基催化剂催化甲醇蒸汽重整的新的合成路线:
CH3OH → HCHO + H2 (10)
HCHO + H2O → HCOOH + H2 (11)
HCOOH → CO2 + H2 (12)
2HCHO → CH3OCHO (13)
CH3OCHO → CH3OH + CO (14)
CO + H2O → CO2 + H2 (8)
图5很显然说明一氧化碳的存在增加了甲醇合成反应(MSR)的活性。而且,图6也可以看出尽管其在一氧化碳合成反应的选择性比过量的纯骨架铜更大;在二氧化碳形成反应中即使一氧化碳浓度超过1 wt.%选择性也超过了80%。从图4可以看出,骨架铜在这种一氧化碳含量水平上对水气转化反应的活性可以忽略不计。因此,我们得出结论:Pour 等 [39]推导的甲醇合成反应中铜催化剂的机理是不正确的,Takezawa 和Iwasa [40] 提出的更加荒唐。进一步讲,似乎反应式(10)–(12)代表的反应机理在铜基催化剂中占优势,反应式 (10)-(8)的机理不占优势。氧化铬和氧化锌的存在使得水气转化反应比较令人满意(反应式8) ,估计是减少了一氧化碳形成的选择性,而一氧化碳的存在使得水气转化反应中铜催化剂表面中毒, 从而观察到了一氧化碳选择性增加的现象。本研究结果与Takezawa & Iwasa’s [40] 的解释的甲醇合成反应的机理以及蒋(姜也可以,自己查查中国百家姓!!!)等采用铜-氧化薪/氧化铝催化剂的发现是一致的。

3.5. 机制为甲醇蒸气重整
等倾吐。 [39]建议甲醇转换在水面前跟随二步。 一个是甲醇分解: CH3OH → CO + 2H2 (9)秒钟是水煤气转移反应: CO + H2O →二氧化碳+ H2 (8)
最近, Takezawa和Iwasa [40], 根据发现甲醛和甲酸中间体, 提出了一条新的路为甲醇蒸气重整基于铜的催化剂:
CH3OH → HCHO + H2 (10)
HCHO + H2O → HCOOH + H2 (11)
HCOOH →二氧化碳+ H2 (12)
2HCHO → CH3OCHO (13)
CH3OCHO → CH3OH + CO (14)
CO + H2O →二氧化碳+ H2 (8)
它是确切从。 5 Co出现提高了活动为MSR。 此外, 它能
被看见从。 6,虽然选择性为CO形成大于在纯净的骨骼铜, 选择性为二氧化碳形成是超出80%,既使当Co集中是超过1无线电报术。%. 从。 4它能被看见包含Co的这个水平骨骼铜有微不足道的活动为水gasshift反应。 所以, 我们可以认为,提出的机制等倾吐。 [39]为铜摧化的MSR反应不是正确的,并且那Takezawa和Iwasa提议的机制[40]是更加振振有词的。 此外, 看起来Eqs代表的机制。 (10) - (12)为基于铜的催化剂和那占优势Eqs代表的机制。 (10) - (8)是较不统治的。

Cr2O3和ZnO出现倾向了WGS反应(Eq。 (8))和占减少的选择性为CO形成, 而Co出现做了Cu表面不活泼为WGS反应, 从而占在CO选择性的被观察的增量。 结果与机制的Takezawa和Iwasa的[这项研究的40]解释为MSR反应和江的研究结果等是一致的。 [41]使用Cu-ZnO/氧化铝催化剂

其中还得自己修改一番