kpmg 2017 校招:tan67°30'-tan22°30'=?
来源:百度文库 编辑:神马品牌网 时间:2024/03/29 17:32:12
不用计算机,简便的!过程!
解:tan67°30'-tan22°30'
=tan67°30'-cot67°30'
=(sin^267°30'-cos^267°30')/(sin67°30'cos67°30')
=-cos135°/sin135°
=-1
cot22°30'-tan22°30'
=2/sin45°
=2根号2