红木床图片及价格表:一道计算题 急用
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计算: (2x+1)^2(2x-1)^2 (要步骤)
(2x+1)^2(2x-1)^2
=(2x+1)(2x-1)(2x+1)(2x-1)
=(4x^2-1)(4x^2-1)
=16x^4-8x^2+1
这道题太简单了,你是初一的吧?
(2x+1)^2(2x-1)^2
=[(2x+1)(2x-1)]^2
=[4x^2-1]^2
=16x^4+1-8x^2
给分!
(2x+1)^2(2x-1)^2
=[(2x+1)(2x-1)]^2
=[4x^2-1]^2
=16x^4+1-8x^2
(2x+1)(2x-1)(2x+1)(2x-1)
=(4x^2-1)^2
=16x^4-8x^2+1
原式=(2x+1)(2x-1)(2x+1)(2x-1)
=(4x^2-1)^2
=16x^4-8x^2+1
(4X^2-1)^2=16X^4+1-8X^2